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  • #12
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  • 2018-06-04T05:43:53Z
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  • Hi guys, this is my code and it’s currently working. What do you think? /* Looping through images */ for (i = 1; i <= 5; i++) { var newImage = document.createElement(‘img’); newImage.setAttribute(‘src’, ‘./images/pic’ + i + ‘.jpg’); thumbBar.appendChild(newImage); newImage.onclick = getTheImage; function getTheImage(e, src) { var src = e.target.getAttribute(‘src’); displayedImage.setAttribute(‘src’, src); }; }; /* Wiring up the Darken/Lighten button */ btn.onclick = changeOverlay; function changeOverlay () { var cl = btn.getAttribute(‘class’); if (cl === ‘dark’) { btn.setAttribute(‘class’, ‘light’); btn.textContent = ‘Lighten’; overlay.style.backgroundColor = ‘rgba(0,0,0,0.5)’; } else { btn.setAttribute(‘class’, ‘dark’); btn.textContent = ‘Darken’; overlay.style.backgroundColor = ‘rgba(0,0,0,0)’; } };
  • Hi Mattia, Your code doesn’t look too at at all — nice job! One bit of feedback I can give you — in the following block: function getTheImage(e, src) { var src = e.target.getAttribute('src'); displayedImage.setAttribute('src', src); } } You don’t need to define the src parameter in the function, as you are getting src inside the function body in the second line instead. So the following would work fine: function getTheImage(e) { var src = e.target.getAttribute('src'); displayedImage.setAttribute('src', src); } }
  • Hi Mattia, Your code doesn’t look too at at all — nice job! One bit of feedback I can give you — in the following block: function getTheImage(e, src) { var src = e.target.getAttribute('src'); displayedImage.setAttribute('src', src); } } You don’t need to define the src parameter in the function, as you are getting src inside the function body in the second line instead. So the following would work fine: function getTheImage(e) { var src = e.target.getAttribute('src'); displayedImage.setAttribute('src', src); } }
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  • "Image gallery" assessment
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